• Đề thi kết thúc học phần học phần: Hoá học đại cương - Học kì I – Năm học: 2013 – 2014Đề thi kết thúc học phần học phần: Hoá học đại cương - Học kì I – Năm học: 2013 – 2014

    Câu 2 (3 điểm) Trên cơ sở phương pháp MO, hãy: 2.1. (2đ) Xây dựng giản đồ MO cho các phân tử B2+ 2 ; F22- 2.2. (1đ) Từ kết quả thu được ở câu 2.1, hãy giải thích tại sao các hợp chất nói trên không tồn tại? Cho biết: B (Z = 5) ; F (Z = 9)

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  • Hóa học - Chapter 14: Ethers, epoxides, and sulfidesHóa học - Chapter 14: Ethers, epoxides, and sulfides

    An epoxide is higher in energy than an acyclic ether by about 25 kcal/mol ring strain. Release of the ring strain makes the opening of an epoxide thermodynamically favored. Strong bases, such as Grignards and organolithiums, open the epoxide ring by attacking the less hindered carbon.

    ppt46 trang | Chia sẻ: nguyenlam99 | Ngày: 10/01/2019 | Lượt xem: 962 | Lượt tải: 0

  • Hóa học - Chapter 13: Nuclear magnetic resonance spectroscopyHóa học - Chapter 13: Nuclear magnetic resonance spectroscopy

    Nuclear Magnetic Resonance Imaging is a noninvasive diagnostic tool. “Nuclear” is omitted because of public’s fear that it would be radioactive. Computer puts together “slices” to get 3-D images. Tumors are readily detected.

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  • Hóa học - Chapter 12: Infrared spectroscopy and mass spectrometryHóa học - Chapter 12: Infrared spectroscopy and mass spectrometry

    Isotopes are present in their usual abundance. Carbon has a 13C isotope present in 1.1% abundance. The spectrum will show the normal M+ and small M+1 peak. Bromine has two isotopes: 79Br (50.5%) and 81Br (49.5%). Since the abundances are almost equal, there will be an M+ peak and and M+2 peak of equal height.

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  • Hóa học - Chapter 11: Reactions of alcoholsHóa học - Chapter 11: Reactions of alcohols

    Easy for inorganic salts: CrO42- reduced to Cr2O3. KMnO4 reduced to MnO2. Oxidation: Gain of O, O2, or X2; loss of H2. Reduction: Gain of H2 (or H-); loss of O or O2; and loss of X2. The gain or loss of H+, H2O, HX, etc. is neither an oxidation nor a reduction.

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  • Hóa học - Chapter 10: Structure and synthesis of alcoholsHóa học - Chapter 10: Structure and synthesis of alcohols

    The thiolate will attack the carbon displacing the halide. This is an SN2 reaction so methyl halides will react faster than primary alkyl halides. To prevent dialylation use a large excess of sodium hydrosulfide with the alkyl halide.

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  • Hóa học - Chapter 9: AlkynesHóa học - Chapter 9: Alkynes

    Permanganate Oxidation of Alkynes to Carboxylic Acids If potassium permanganate is used under basic conditions or if the solution is heated too much, an oxidative cleavage will take place and two molecules of carboxylic acids will be produced

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  • Hóa học - Chapter 8: Reactions of alkenesHóa học - Chapter 8: Reactions of alkenes

    An alkene (monomer) can add to another molecule like itself to form a chain (polymer). Three methods: Cationic, a carbocation intermediate Free radical Anionic, a carbanion intermediate (rare)

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  • Hóa học - Chapter 7: Structure and synthesis of alkenesHóa học - Chapter 7: Structure and synthesis of alkenes

    Use concentrated sulfuric or phosphoric acid, remove low-boiling alkene as it forms to shift the equilibrium, and increase the yield of the reaction. Carbocation intermediate: 3º alcohols react faster than 2º. Primary alcohols are the least reactive. Rearrangements are common. Reaction obeys Zaitsev’s rule.

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  • Hóa học - Chapter 6: Acids and basesHóa học - Chapter 6: Acids and bases

    Brønsted-Lowry bases are H+ acceptors any material that has atoms with lone pairs can potentially be a Brønsted-Lowry base because of the molecular structure, often one atom in the molecule is more willing to accept H+ transfer than others NH3(aq) is basic because NH3 accepts an H+ from H2O, forming OH–(aq) water acts as acid, donating H+

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