Real - Time systems - Week 3: Task and task synchronization
Suppose that system has only one resource for each
type such as 1 printer, 1 tape driver, 1 plotter .
To detect a deadlock (the easiest technique)
Draw a graph of relationship between processes and resources
If at least one cycle can be detected, a deadlock exists.
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NLT, SoICT, 2015
Real-time Systems
Ngo Lam Trung
Dept. of Computer Engineering
Week 3:
Task and Task Synchronization
NLT, SoICT, 2015
Task
Task synchronization
Semaphore and mutex
Philosopher’s problem
Deadlock
Content
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Defining a task
Independent thread of execution that can compete with
concurrent tasks for processor execution time.
Thus, schedulable & allocated a priority level according to the
scheduling algorithm
Elements of a task
Unique ID
Task control block (TCB)
Stack
Priority (if part of a preemptive scheduling plan)
Task routine
NLT, SoICT, 2015
Elements of a task
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Task states & scheduling
Task states:
Ready state
Running state
Blocked state
Scheduler
determines each
task’s state.
running
blockedready
dispatched
preempted
blocked
unblocked
unblocked
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Task states
ready state-the task is ready to run but cannot because
a higher priority task is executing.
blocked state-the task has requested a resource that is
not available, has requested to wait until some event
occurs, or has delayed itself for some duration.
running state-the task is the highest priority task and is
running.
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Typical task structure(1)
Typical task structures:
Run-to-completion task: Useful for initialization & startup
tasks
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Typical task structure(2)
Typical task structures:
Endless-loop task: Work in an application by handling inputs
& outputs
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Semaphores
In multi-task systems, concurrently-running tasks should
be able to
synchronize their execution, and
to coordinate mutual exclusive access to shared resources.
What is semaphore?
A kernel object to realize synchronization & mutual exclusion
One or more threads of execution can acquire & release to
execute an operation to be synchronized or to access to a
shared resource.
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Semaphore elements
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Defining semaphore
Elements of semaphores assigned by the kernel
Semaphore control block (SCB)
Semaphore ID (unique in the system)
Value (binary or count)
Task-waiting list
Classification of semaphores:
Binary semaphore
Counting semaphore
Mutex
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Binary semaphore
Provides binary state of unavailable/available (or empty/full)
Task 1 Task 2
Semaphore
Acquire semaphore
(P operation)
Can’t acquire semaphore
during Task 1’s
acquirement
Release semaphore
(V operation)
Acquire semaphore (P
operation)
Initial value1: availablevalue 0: unavailablevalue 1: available
Release semaphore
(V operation)
l 1 av ilable
Task 3
Any tasks can release semaphore
if it is global resource
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Counting semaphore
If the value of a semaphore is n, it can be acquired n
times concurrently.
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Mutual exclusion (MUTEX) semaphores
Special binary semaphore
Has states of locked/unlocked & lock count
Difference: signaling vs protecting
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Mutual exclusion (MUTEX) semaphores
Special features of MUTEX
Ownership: When a task acquires the mutex, no other task can
release it.
- General semaphores: released by any task
Recursive locking: allows the owner task to re-acquire the mutex
multiple times in the locked state
- The number of times of recursive acquirement is managed
by lock count.
- Useful when the owner task requires exclusive access to
shared resource and calls routines that also require the
same resource
- Problem: recursion and deadlock
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Mutual exclusion (MUTEX) semaphores
Special features of MUTEX
Task deletion safety: avoiding a task deletion while it is locking a
mutex
Priority inversion avoidance:
- Priority inversion problem: a higher priority task is blocked and is
waiting for a resource being used by a lower priority task, which has
itself been preempted by an unrelated medium-priority task
- To avoid priority inversion additional protocols are required, eg
priority inheritance protocol, or priority ceiling protocol
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Semaphore vs Mutex
All processes can release semaphore
Only owner is able to unlock mutex
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Typical semaphore use
Semaphore are used for:
Synchronizing execution of tasks
Coordinating access to a shared resource
Synchronization design requirements
Wait-and-signal
Multiple-task wait-and-signal
Credit-tracking
Single shared-resource-access
Recursive shared-resource-access
Multiple shared-resource access
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Typical semaphore uses
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Example:
Consumer – producer problem
Producer:
Task to read data from input device,
Data transferred to 4KB shared buffer memory
Consumer:
Task to read and process data from buffer memory
Synchronization problem
Solution 1: binary semaphore for buffer memory access
Other solution?
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Example: The Dining Philosophers Problem
Five philosophers seated around a
circular table with a plate of
spaghetti for each.
Between each pair of plates is one
fork
The spaghetti is so slippery that a
philosopher needs two forks to eat
it.
When a philosopher gets hungry,
he tries to acquire his left and right
fork
Problem: not enough forks for all
Write a program to control philosophers concurrently without getting stuck?
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Solution 1:
#define N 5/* number of philosophers */
void philosopher(int i)/* i: philosopher number, from 0 to 4 */
{
while (TRUE) {
think( ); /* philosopher is thinking */
take_fork(i); /* take left fork */
take_fork((i+1) % N);/* take right fork; */
eat(); /* yum-yum, spaghetti */
put_fork(i); /* Put left fork back on the table */
put_fork((i+1) % N);/* put right fork back table */
}
}
This is non-solution, because of potential deadlock. Why?
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Solution 2:
If philosopher could not acquire fork:
Wait for a random duration
Retry
Simple and efficient
Minimize lock-state time
But not lock-state free
Cannot be used in critical system
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Solution 3
#define N 5 /* Number of philosphers */
#define RIGHT(i) (((i)+1) %N)
#define LEFT(i) (((i)==N) ? 0 : (i)+1)
typedef enum { THINKING, HUNGRY, EATING } phil_state;
phil_state state[N];
semaphore mutex =1;
semaphore s[N]; /* one per philosopher, all 0 */
void test(int i) {
if ( state[i] == HUNGRY && state[LEFT(i)]!= EATING &&
state[RIGHT(i)] != EATING )
{
state[i] = EATING;
up(s[i])
}
}
NLT, SoICT, 2015
Solution 3
void get_forks(int i){
down(mutex);
state[i] = HUNGRY;
test(i);
up(mutex);
down(s[i]); //lock
}
void put_forks(int i){
down(mutex);
state[i]= THINKING;
test(LEFT(i));
test(RIGHT(i));
up(mutex);
}
void philosopher(int process)
{
while(1)
{
think();
get_forks(process);
eat();
put_forks(process);
}
}
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Deadlock
Task uses resources
Two types of resources
Preemtible: memory, printer
Non-preemtible: CD-W drive in disc burning process
Potential deadlock with preemtible resources can be
resolved (imagine the case philosophers can share forks
without cleaning!)
Deadlock involves non-preemtible resources
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Deadlock
Deadlock definition:
A set of processes is deadlocked if each process in the set is
waiting for an event that only another process in the process
can occur.
Conditions for deadlock
Mutual exclusion condition: a resource that cannot be used by
more than one process at a time
Hold and wait condition: processes already holding resources
may request new resources
No preemption condition: No resource can be forcibly removed
from a process holding it, resources can be released only by the
explicit action of the process
Circular wait condition: two or more processes form a circular
chain where each process waits for a resource that the next
process in the chain holds
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Deadlock modeling
Process A holds
resource R
Process B
acquires
resource R
Deadlock
Process C is waiting resource T, which is
currently holding by process D.
Process D is waiting resource U, which
is currently holding by process C.
A
BR
S C
DT
U
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Deadlock detection and recovery
Let deadlock occurs, tries to detect and attempt recovery
if necessary.
2 methods to detect deadlock
Deadlock detection with one resource of each type
Deadlock detection with multiple resource of each type
3 methods to recovery from deadlock
Recovery through preemption
Recovery through rollback
Recovery through killing processes
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Deadlock detection with one resource
Suppose that system has only one resource for each
type such as 1 printer, 1 tape driver, 1 plotter.
To detect a deadlock (the easiest technique)
Draw a graph of relationship between processes and resources
If at least one cycle can be detected, a deadlock exists.
NLT, SoICT, 2015
Process A holds R and wants S
Process B holds nothing but wants T
Process C holds nothing but wants S
Process D holds U and wants S and T
Process E holds T and wants V
Process F holds W and wants S
Process G holds V and wants U
Example
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