Limit of a function and one - Sided limits
Intuitive Definition
The
limit of f (x) as x approaches a from the right is L
if the values of f (x) get closer and closer to L as the values of x get closer and
closer to a, but are greater than a
34 trang |
Chia sẻ: nguyenlam99 | Lượt xem: 831 | Lượt tải: 0
Bạn đang xem trước 20 trang tài liệu Limit of a function and one - Sided limits, để xem tài liệu hoàn chỉnh bạn click vào nút DOWNLOAD ở trên
Limit of a Function and
One-sided limits
Mathematics 53
Institute of Mathematics (UP Diliman)
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 1 / 37
For today
1 Limit of a Function: An intuitive approach
2 Evaluating Limits
3 One-sided Limits
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 2 / 37
Introduction
Given a function f (x) and a ∈ R,
what is the value of f at x near a,
but not equal to a?
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 4 / 37
Illustration 1
Consider f (x) = 3x− 1.
What can we say about values of f (x) for values of x near 1 but not equal to 1?
x f (x)
0 −1
0.5 0.5
0.9 1.7
0.99 1.97
0.99999 1.99997
x f (x)
2 5
1.5 3.5
1.1 2.3
1.001 2.003
1.00001 2.00003
Based on the table, as x gets closer and closer to 1, f (x) gets closer and closer
to 2.
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 5 / 37
Illustration 1
x f (x)
0 −1
0.5 0.5
0.9 1.7
0.99 1.97
0.99999 1.99997
−1 1 2 3
−1
1
2
3
4
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 6 / 37
Illustration 1
x f (x)
2 5
1.5 3.5
1.1 2.3
1.001 2.003
1.00001 2.00003
−1 1 2 3
−1
1
2
3
4
As x gets closer and closer to 1, f (x) gets closer and closer to 2.
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 7 / 37
Illustration 2
Consider: g(x) =
3x2 − 4x+ 1
x− 1
=
(3x− 1)(x− 1)
x− 1
= 3x− 1, x 6= 1
−1 1 2 3
−1
1
2
3
4
As x gets closer and closer to 1, g(x) gets closer and closer to 2.
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 8 / 37
Illustration 3
Consider: h(x) =
3x− 1, x 6= 10, x = 1
−1 1 2 3
−1
1
2
3
4
As x gets closer and closer to 1, h(x) gets closer and closer to 2.
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 9 / 37
Limit
Intuitive Notion of a Limit
a ∈ R, L ∈ R
f (x): function defined on some open interval containing a, except possibly at a
The limit of f (x) as x approaches a is L
if the values of f (x) get closer and closer to L as x assumes values getting closer
and closer to a but not reaching a.
Notation:
lim
x→a f (x) = L
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 10 / 37
Examples
f (x) = 3x− 1
−1 1 2 3
−1
1
2
3
4
lim
x→1
(3x− 1) = 2
Note: In this case, lim
x→1
f (x) = f (1).
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 11 / 37
Examples
g(x) =
3x2 − 4x+ 1
x− 1
−1 1 2 3
−1
1
2
3
4 lim
x→1
3x2 − 4x+ 1
x− 1 = 2
Note: Though g(1) is undefined,
lim
x→1
g(x) exists.
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 12 / 37
Examples
h(x) =
3x− 1, x 6= 10, x = 1
−1 1 2 3
−1
1
2
3
4
lim
x→1
h(x) = 2
Note: h(1) 6= lim
x→1
h(x).
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 13 / 37
Some Remarks
Remark
In finding lim
x→a f (x):
We only need to consider values of x very close to a but not exactly at a.
Thus, lim
x→a f (x) is NOT NECESSARILY the same as f (a).
We let x approach a from BOTH SIDES of a.
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 14 / 37
Some Remarks
If f (x) does not approach any
particular real number as x
approaches a, then we say
lim
x→a f (x) does not exist (dne).
e.g.
H(x) =
1, x ≥ 0
0, x < 0
−3 −2 −1 1 2 3
1
2
3
0
lim
x→0
H(x) = 0? No.
lim
x→0
H(x) = 1? No.
lim
x→0
H(x) dne
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 15 / 37
Limit Theorems
Theorem
If lim
x→a f (x) exists, then it is unique.
If c ∈ R, then lim
x→a c = c.
lim
x→a x = a
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 17 / 37
Limit Theorems
Theorem
Suppose lim
x→a f (x) = L1 and limx→a g(x) = L2. Let c ∈ R, n ∈ N.
lim
x→a[ f (x)± g(x)] = limx→a f (x)± limx→a g(x) = L1 ± L2
lim
x→a[ f (x)g(x)] =
(
lim
x→a f (x)
) (
lim
x→a g(x)
)
= L1L2
lim
x→a[c f (x)] = c limx→a f (x) = cL1
lim
x→a
f (x)
g(x)
=
lim
x→a f (x)
lim
x→a g(x)
=
L1
L2
, provided L2 6= 0
lim
x→a ( f (x))
n =
(
lim
x→a f (x)
)n
= (L1)n
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 18 / 37
Evaluate: lim
x→−1
(2x2 + 3x− 4)
lim
x→−1
(2x2 + 3x− 4) = lim
x→−1
2x2 + lim
x→−1
3x− lim
x→−1
4
= 2
(
lim
x→−1
x2
)
+ 3
(
lim
x→−1
x
)
− lim
x→−1
4
= 2
(
lim
x→−1
x
)2
+ 3
(
lim
x→−1
x
)
− lim
x→−1
4
= 2(−1)2 + 3(−1)− 4
= −5
In general:
Remark
If f is a polynomial function, then lim
x→a f (x) = f (a).
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 19 / 37
Evaluate: lim
x→−2
4x3 + 3x2 − x+ 1
x2 + 2
lim
x→−2
4x3 + 3x2 − x+ 1
x2 + 2
=
lim
x→−2
(4x3 + 3x2 − x+ 1)
lim
x→−2
(x2 + 2)
=
4(−2)3 + 3(−2)2 − (−2) + 1
(−2)2 + 2
= −17
6
Remark
If f is a rational function and f (a) is defined, then lim
x→a f (x) = f (a).
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 20 / 37
Theorem
Suppose lim
x→a f (x) exists and n ∈ N. Then,
lim
x→a
n
√
f (x) = n
√
lim
x→a f (x),
provided lim
x→a f (x) > 0 when n is even.
lim
x→3
√
3x− 1 =
√
lim
x→3
(3x− 1) =
√
8 = 2
√
2
lim
x→−1
3
√
x+ 4
x− 2 =
3
√−1+ 4
−1− 2 = −1
lim
x→7/2
4
√
3− 2x dne
lim
x→2
√
x2 − 4 =? (for now)
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 21 / 37
Evaluate: lim
x→3
(
2x2 −√5x+ 1
x3 − x+ 4
)3
lim
x→3
(
2x2 −√5x+ 1
x3 − x+ 4
)3
=
limx→3 2x2 −
√
lim
x→3
(5x+ 1)
lim
x→3
(x3 − x+ 4)
3
=
(
18− 4
28
)3
=
1
8
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 22 / 37
Consider: g(x) =
3x2 − 4x+ 1
x− 1 . From earlier, limx→1 g(x) = 2.
Can we arrive at this conclusion computationally?
Note that lim
x→1
(
3x2 − 4x+ 1
)
= 0 and lim
x→1
(x− 1) = 0.
But when x 6= 1, 3x
2 − 4x+ 1
x− 1 =
(3x− 1)(x− 1)
x− 1 = 3x− 1.
Since we are just taking the limit as x → 1,
lim
x→1
3x2 − 4x+ 1
x− 1 = limx→1(3x− 1) = 2.
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 23 / 37
Definition
If lim
x→a f (x) = 0 and limx→a g(x) = 0 then
lim
x→a
f (x)
g(x)
is called an indeterminate form of type
0
0
.
Remarks:
1 If f (a) = 0 and g(a) = 0, then
f (a)
g(a)
is undefined!
2 The limit above MAY or MAY NOT exist.
3 Some techniques used in evaluating such limits are:
Factoring
Rationalization
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 24 / 37
Examples
Evaluate: lim
x→−2
x3 + 8
x2 − 4
(
0
0
)
lim
x→−2
x3 + 8
x2 − 4 = limx→−2
(x+ 2)(x2 − 2x+ 4)
(x+ 2)(x− 2)
= lim
x→−2
x2 − 2x+ 4
x− 2
=
4+ 4+ 4
−2− 2
= −3
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 25 / 37
Examples
Evaluate: lim
x→4
x2 − 16
2−√x
(
0
0
)
lim
x→4
x2 − 16
2−√x = limx→4
x2 − 16
2−√x ·
2+
√
x
2+
√
x
= lim
x→4
(x2 − 16)(2+√x)
4− x
= lim
x→4
(x− 4)(x+ 4)(2+√x)
4− x
= lim
x→4
[−(x+ 4)(2+√x)]
= (−8)(4)
= −32
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 26 / 37
Examples
Evaluate: lim
x→−1
3
√
x+ 1
2x+ 2
(
0
0
)
lim
x→−1
3
√
x+ 1
2x+ 1
= lim
x→−1
3
√
x+ 1
2x+ 1
·
3√x2 − 3√x+ 1
3√x2 − 3√x+ 1
= lim
x→−1
x+ 1
2(x+ 1)( 3
√
x2 − 3√x+ 1)
= lim
x→−1
1
2( 3
√
x2 − 3√x+ 1)
=
1
6
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 27 / 37
Illustration 4
Consider: f (x) =
3− 5x2, x < 1
4x− 3, x ≥ 1
As x → 1, the value of f (x) depends
on whether x 1. −4 −3 −2 −1 1 2 3
−3
−2
−1
1
2
3
4
0
As x approaches 1 through values less than 1, f (x) approaches −2.
As x approaches 1 through values greater than 1, f (x) approaches 1.
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 29 / 37
Illustration 5
Consider: g(x) =
√
x
−2 −1 1 2 3
−1
1
2
0
( )( )( )( )
Since there is no open interval I containing 0 such that g(x) is defined on I, we
cannot let x approach 0 from both sides.
But we can say something about the values of g(x) as x gets closer and closer to
0 from the right of 0.
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 30 / 37
One-sided Limits
Intuitive Definition
The
limit of f (x) as x approaches a from the left is L
if the values of f (x) get closer and closer to L as the values of x get closer and
closer to a, but are less than a.
Notation:
lim
x→a−
f (x) = L
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 31 / 37
One-sided Limits
Intuitive Definition
The
limit of f (x) as x approaches a from the right is L
if the values of f (x) get closer and closer to L as the values of x get closer and
closer to a, but are greater than a
Notation:
lim
x→a+
f (x) = L
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 32 / 37
Theorem
lim
x→a f (x) = L if and only if limx→a−
f (x) = lim
x→a+
f (x) = L
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 33 / 37
f (x) =
3− 5x2, x < 1
4x− 3, x ≥ 1
−4 −3 −2 −1 1 2 3
−3
−2
−1
1
2
3
4
0
lim
x→1−
f (x) = lim
x→1−
(3− 5x2) = −2
lim
x→1+
f (x) = lim
x→1+
(4x− 3) = 1
lim
x→1
f (x) dne
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 34 / 37
Examples
g(x) =
√
x
−2 −1 1 2 3
−1
1
2
0
Based on the graph,
lim
x→0+
√
x = 0
lim
x→0−
√
x dne
lim
x→0
√
x dne
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 35 / 37
Examples
Let p(x) =
√
5− 2x, x ≤ 2
x2 − 2x
2x− 4 , x > 2
lim
x→2−
p(x) = lim
x→2−
√
5− 2x =
√
1 = 1
lim
x→2+
p(x) = lim
x→2+
x2 − 2x
2x− 4 = limx→2+
x(x− 2)
2(x− 2) = limx→2+
x
2
= 1
lim
x→2
p(x) = 1
lim
x→3
p(x) = lim
x→3
x2 − 2x
2x− 4 =
9− 6
6− 4 =
3
2
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 36 / 37
Exercises
1 Evaluate: lim
x→4
3x− 12
3−√2x+ 1
2 Find lim
x→−1
f (x) given: f (x) =
x2 + 1
x− 1 , if x < −1
1−√x+ 5, if x ≥ −1
3 Evaluate: lim
x→2/3
(
6x− 4
3x2 + 4x− 4 +
1
3x+ 2
)
Institute of Mathematics (UP Diliman) Limit of a Function and One-sided limits Mathematics 53 37 / 37
Các file đính kèm theo tài liệu này:
- m53_lec1_1_limits_one_sided1_2079.pdf