Giải tích 1 - Chapter 5: Discrete probability distributions
Electric fuses produced by Ontario Electric are
packaged in boxes of 12 units each.
● Suppose an inspector randomly selects 3 of the 12
fuses in a box for testing. If the box contains exactly
5 defective fuses, what is the probability that the
inspector will find exactly 1 of the 3 fuses defective?
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Chapter 5
DISCRETE PROBABILITY DISTRIBUTIONS
Nguyen Tien Dung, MBA
School of Economics and Management
Website: https://sites.google.com/site/nguyentiendungbkhn
Email: dung.nguyentien3@hust.edu.vn
Main Contents
5.1 Random Variables
5.2 Developing Discrete Probability
Distributions
5.3 Expected Value And Variance
5.4 Bivariate Distributions, Covariance, and
Financial Portfolios
5.5 Binomial Probability Distribution
5.6 Poisson Probability Distribution
5.7 Hypergeometric Probability Distribution
© Nguyễn Tiến Dũng Applied Statistics for Business 2
5.1 RANDOM VARIABLES
● A numerical description of the outcome of
an experiment.
● A variable that assume random values,
we don’t know in advance
● Example:
● The upper face of a dice
● The score of customer satisfaction in a
survey
● Time between customer arrivals in minutes
● Two types:
● Discrete
● Continuous
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A discrete random variable
●A type of random variables that assume a
finite number of values or an infinite sequence
of discrete values
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Continuous Random Variables
●A random variable that may assume any
numerical value in an interval or collection of
intervals
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5.2 DISCRETE PROBABILITY DISTRIBUTIONS
● Required conditions for a discrete
probability function:
● Example: the number of automobiles sold
during a day at Dicarlo motors (Table 5.4)
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x f(x)
0 0.18
1 0.39
2 0.24
3 0.14
4 0.04
5 0.01
( ) 0
( ) 1
f x
f x
Discrete Uniform Probability Function
● f(x) = 1/n
● n = the number of values the random variable may have
● Example:
● x = the number of dots on the upward face of a dice
● x = 1, 2, 3, 4, 5, 6
● f(x) = 1/6
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5.3 EXPECTED VALUE AND VARIANCE
●Expected value
E(x)
● 𝐸 𝑥 = 𝜇 = 𝑥𝑓(𝑥)
● Example:
Calculation of the
expected value for
the number of
automobiles sold
during a day at
Dicarlo Motors
● Table 5.5
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●Variance
● 𝑉𝑎𝑟 𝑥 = 𝜎2 = 𝑥 − 𝜇 2𝑓(𝑥)
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5.4 Bivariate Distribution
●A probability distribution involving two random
variables is called a bivariate probability
distribution.
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A Bivariate Empirical Discrete Probability
Distribution
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Covariance
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Correlation Coefficient
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Financial Applications
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E(ax+bx) and Var(ax+by)
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5.5 BINOMIAL PROBABILITY DISTRIBUTION
● Properties of a binomial experiment
1. The experiment consists of a
sequence of n identical trials.
2. Two outcomes are possible on each
trial. We refer to one outcome as a
success and the other outcome as
a failure.
3. The probability of a success,
denoted by p, does not change from
trial to trial. Consequently, the
probability of a failure, denoted by 1
p, does not change from trial to trial.
4. The trials are independent.
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Martin Clothing Store Problem:
The Tree Diagram
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Combination (n,x)
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●Martin Clothing Store: Among the n = 3
customers, what is the probability of having x
customers who make purchases?
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Graphical Representation Of The Probability Distribution
For The Number Of Customers Making A Purchase
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Using Tables of Binomial Probabilities
● Appendix B
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Expected Value and
Variance for the
Binomial Distribution
● 𝐸 𝑥 = 𝜇 = 𝑛𝑝
● 𝑉𝑎𝑟 𝑥 = 𝜎2 = 𝑛𝑝(1 − 𝑝)
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5.6 POISSON PROBABILITY
DISTRIBUTION
● Properties of a
1. The probability of an occurrence is the same for
any two intervals of equal length.
2. The occurrence or nonoccurrence in any interval is
independent of the occurrence or nonoccurrence in
any other interval.
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An Example Involving Time Intervals
● Suppose that we are interested in the number of arrivals at the drive-up teller
window of a bank during a 15-minute period on weekday mornings.
● If we can assume that the probability of a car arriving is the same for any two
time periods of equal length and that the arrival or non-arrival of a car in any
time period is independent of the arrival or nonarrival in any other time period,
the Poisson probability function is applicable.
● Suppose these assumptions are satisfied and an analysis of historical data
shows that the average number of cars arriving in a 15-minute period of time is
10.
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● The probability function:
● The probability of exactly
5 arrivals in 15 minutes
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An Example Involving Length or Distance Intervals
● Suppose we are concerned with the occurrence of major defects in a highway
one month after resurfacing.
● We will assume that the probability of a defect is the same for any two highway
intervals of equal length and that the occurrence or nonoccurrence of a defect in
any one interval is independent of the occurrence or nonoccurrence of a defect
in any other interval.
● Suppose we learn that major defects one month after resurfacing occur at the
average rate of two per mile. (2 defects/mile)
● Let us find the probability of no major defects in a particular 3-mile section of the
highway.
● Because we are interested in an interval with a length of 3 miles, μ = (2
defects/mile)(3 miles) = 6 represents the expected number of major defects
over the 3-mile section of highway.
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Probability of no major defects over the 3-mile
section of highway ( 0)
!
x
e
f x
x
5.7 HYPERGEOMETRIC PROBABILITY
DISTRIBUTION
● Similar to binomial distribution
● Differences:
● Trials are not independent
● Probability of success changes from trial to trial
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Example
● Electric fuses produced by Ontario Electric are
packaged in boxes of 12 units each.
● Suppose an inspector randomly selects 3 of the 12
fuses in a box for testing. If the box contains exactly
5 defective fuses, what is the probability that the
inspector will find exactly 1 of the 3 fuses defective?
© Nguyễn Tiến Dũng Applied Statistics for Business 33
Exercises for Homework
Section Exercises
5.1 3, 4, 5, 6
5.2 9, 11, 13
5.3 17, 19, 20, 21
5.4 27 (add: to compute Var(x+y)), 28
5.5 33, 34, 35
5.6 45, 46, 47, 48
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