Giải tích 1 - Chapter 4: Introduction to probability
Example:
● Two suppliers provide products to a business customer
● Supplier 1 provides 65% of product quantity
● Supplier 2 provides 35% of product quantity
● 98% products of Supplier 1 are met quality standards
(Good), 2% are Bad.
● 95% products of Supplier 2 are met quality standards
(Good), 5% are Bad.
● Take randomly a product provided and check its quality.
The result is that product failed to meet quality
standards.
● What is the probability that the product was come from
Supplier 1? Supplier 2?
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Chapter 4
INTRODUCTION TO PROBABILITY
Nguyen Tien Dung, MBA
School of Economics and Management
Website: https://sites.google.com/site/nguyentiendungbkhn
Email: dung.nguyentien3@hust.edu.vn
Main Contents
4.1 EXPERIMENTS, COUNTING RULES AND ASSIGNING
PROBABILITIES
4.2 EVENTS AND THEIR PROBABILITIES
4.3 SOME BASIC RELATIONSHIPS OF PROBABILITY
4.4 CONDITIONAL PROBABILITY
4.5 BAYES’ THEOREM
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4.1 EXPERIMENTS, COUNTING RULES,
AND ASSIGNING PROBABILITIES
● Sample space for an experiment:
● the set of all experiment outcomes
● An experiment outcome is also called
a sample point
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Probability As A Numerical Measure Of The
Likelihood Of An Event Occurring
●S = {Head; Tail}
●S = {Defective, Nondefective}
●S = {1, 2, 3, 4, 5, 6}
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Counting Rules, Combinations, and Permutation
● Counting Rules
● Being able to identify and count the experimental outcomes is
a necessary step in assigning probabilities.
● Multiple-step experiments
● Example 1: Toss 2 coints
● Example 2: Kentucky Power & Light Company Construction
Project (KP&L Project)
● Tree diagram
● a graphical representation that helps in visualizing a multiple-step
experiment.
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The Tree Diagram For the Tossing-2-Coint
Experiment
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The Tree Diagram for the KP&L Project
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Combinations
● Example: There are 4 football teams, playing in a
tournament. Each will meet the rest once. How
many football matches will the tournament have?
●Do it in 2 ways: manually and using C(N,n).
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Permutations
●Example: There are 5 digits: 1, 2, 3, 4, 5. How
many two-digit numbers could be formed
from these five digits.
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Assigning Probabilities
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Assigning Probabilities
●Classical method
● No. of favourable outcomes (computation) / Total
possible outcomes
● When all experimental outcomes are equally likely
●Relative frequency
● Actual data
● Frequency of occurrences of interested outcomes /
Total actual outcomes
●Subjective method
● A method of assigning probabilities on the basis of
judgment
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Classical method
●Appropriate when all the experimental
outcomes are equally likely.
● If n experimental outcomes are possible, a
probability of 1/n is assigned to each
experimental outcome.
●Example 1: toss a coin
●Example 2: roll a dice
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Relative frequency method
● Appropriate when data are
available to estimate the
proportion of the time the
experimental outcome will occur
if the experiment is repeated a
large number of times.
● Example: a study of waiting times
in the X-ray department for a local
hospital. A clerk recorded the
number of patients waiting for
service at 9:00 a.m. on 20
successive days and obtained the
following results.
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Number of
Waiting
Number of Days
Outcome Occurred
0 2
1 5
2 6
3 4
4 3
Total 20
Number of
Waiting
Probability of
Outcome Occurred
0 2/20 = 0.1
1 5/20 = 0.25
2 6/20 = 0.3
3 4/20 = 0.2
4 3/20 = 0.15
Total 20/20 =1.00
Assigning
Probabilities
by the Relative
Frequency
Method
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4.2 EVENTS AND THEIR PROBABILITIES
● An event is a collection of sample points
● KP&L Project
● C = {(2,6), (2, 7), (2,8), (3,6), (3,7), (4,6)}
● Event C includes many sample points
● One event may be comprised of many events
● L = the event that the projects is completed in LESS than 10 months
● L = {(2,6), (2,7), (3, 6)}
● M = the event that the project is completed in 10 months or more than
10 months
● M = {(2,8), (3,7), (4,6)
● C = {L, M}
● Probability of an event
● The sum of the probability of the sample points in the event.
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4.3 SOME BASIC RELATIONSHIPS OF PROBABILITY
●Complement of an event
●P(A) = 1 – P(Ac)
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Union of Two Events
●The union of A and B is the event containing all
sample points belonging to A or B or both. The
union is denoted by A B.
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Intersection of Two Events
●Given two events A and B, the intersection of A
and B is the event containing the sample points
belonging to both A and B. The intersection is
denoted by A B.
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Addition Law
● 𝑃 𝐴 ∪ 𝐵 = 𝑃 𝐴 + 𝑃 𝐵 − 𝑃(𝐴 ∩ 𝐵)
● Example: a small assembly plant with 50
employees. Each worker is expected to complete
work assignments on time and in such a way that
the assembled product will pass a final inspection.
or assembling a defective product.
● 5 of the 50 workers completed work late,
● 6 of the 50 workers assembled a defective product,
● 2 of the 50 workers both completed work late and
assembled a defective product.
● Questions: Take randomly an employee. What is the
probability taking an employee with a poor performance
rating?
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Addition Law for Mutually Exclusive Events
●Two events are said to be mutually exclusive if
the events have no sample points in common.
P(A B) = P(A) + P(B)
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4.4 CONDITIONAL PROBABILITY
●The probability of event A given the condition
that event B has occurred: P(A | B)
●Example:
● There are 5 white balls and 3 black balls in a box.
Draw randomly 2 balls consecutively. What is the
probability of having 2 white balls?
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●Example: The situation of promotion status of
male and female officers in a police force
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Joint Probability Table
●M = event an officer is a man
● A = event an officer is promoted
● P(M A)= 288/1200 = 0.24
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288 288 / 1200 ( ) 0.24
( | ) 0.30
960 960 / 1200 ( ) 0.80
P A M
P A M
P M
36 36 / 1200 ( ) 0.03
( | ) 0.15
240 240 / 1200 ( ) 0.2
P A W
P A W
P W
Conditional Probability
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( )
( | )
( )
P A B
P A B
P B
( )
( | )
( )
P A B
P B A
P A
Independent Events
●Two events A and B are independent if P(A | B)
= P(A) or P(B | A) = P(B).
●Example:
● Toss 2 coins: A = head of the first coin; B = head of
the second coin
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Multiplication Law
● In general
● P(A B) = P(A).P(B | A) = P(B).P(A | B)
● For independent events
● P(A B) = P(A).P(B)
● Example: A service station manager who knows
from past experience that 80% of the customers
use a credit card when they purchase gasoline.
What is the probability that the next two
customers purchasing gasoline will each use a
credit card?
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●C1 = the event the first customer use the credit
card
●C2 = the event the second customer use the
credit card
●C1 and C2 are independent events
●P(C1.C2) = P(C1).P(C2) = (0.8).(0.8) = 0.64
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4.5 BAYES’ THEOREM
●Meaning:
© Nguyễn Tiến Dũng Applied Statistics in Business 29
Bayes’ Theorem
© Nguyễn Tiến Dũng Applied Statistics in Business 30
● Example:
● Two suppliers provide products to a business customer
● Supplier 1 provides 65% of product quantity
● Supplier 2 provides 35% of product quantity
● 98% products of Supplier 1 are met quality standards
(Good), 2% are Bad.
● 95% products of Supplier 2 are met quality standards
(Good), 5% are Bad.
● Take randomly a product provided and check its quality.
The result is that product failed to meet quality
standards.
● What is the probability that the product was come from
Supplier 1? Supplier 2?
© Nguyễn Tiến Dũng Applied Statistics in Business 31
Probability Tree for Two-supplier Example
© Nguyễn Tiến Dũng Applied Statistics in Business 32
Tabular Approach
© Nguyễn Tiến Dũng Applied Statistics in Business 33
Exercises for Homework
●4.1: Exercises 6, 7, 9, 10, 13
●4.2: Exercises 16, 17, 19, 21
●4.3: Exercises 24, 25, 28
●4.4: Exercises 32, 33, 37
●4.5: Exercises 40, 41, 42
© Nguyễn Tiến Dũng Applied Statistics in Business 34
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