Hóa học - Chapter 18: Ketones and aldehydes

Forms hydrazone, then heat with strong base like KOH or potassium tert-butoxide. Use a high-boiling solvent: ethylene glycol, diethylene glycol, or DMSO. A molecule of nitrogen is lost in the last steps of the reaction.

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Chapter 18Copyright © 2010 Pearson Education, Inc.Organic Chemistry, 7th Edition L. G. Wade, Jr.Ketones and AldehydesChapter 18*Carbonyl CompoundsChapter 18*Carbonyl StructureCarbon is sp2 hybridized.C═O bond is shorter, stronger, and more polar than C═C bond in alkenes.Chapter 18*Ketone NomenclatureNumber the chain so that carbonyl carbon has the lowest number.Replace the alkane -e with -one.3-methyl-2-butanone4-hydroxy-3-methyl-2-butanoneCH3COCHCH3CH3CH3COCHCH3CH2OH12341234Chapter 18*Ketone Nomenclature (Continued)For cyclic ketones, the carbonyl carbon is assigned the number 1.3-bromocyclohexanoneOBr13Chapter 18*CH3CH2CHCH3CH2CHOAldehydes NomenclatureThe aldehyde carbon is number 1.IUPAC: Replace -e with -al. 3-methylpentanal1235Chapter 18*Carbonyl as SubstituentOn a molecule with a higher priority functional group, a ketone is an oxo and an aldehyde is a formyl group.Aldehydes have a higher priority than ketones.3-methyl-4-oxopentanal3-formylbenzoic acid13413CH3CCHCH3CH2CHOOCOOHCHOChapter 18*Common Names for KetonesNamed as alkyl attachments to —C═O.Use Greek letters instead of numbers.methyl isopropyl ketonea-bromoethyl isopropyl ketoneCH3COCHCH3CH3CH3CHCOCHCH3CH3BrChapter 18*Historical Common NamesacetoneacetophenonebenzophenoneChapter 18*Boiling PointsKetones and aldehydes are more polar, so they have a higher boiling point than comparable alkanes or ethers.They cannot hydrogen-bond to each other, so their boiling point is lower than comparable alcohol.Chapter 18*Solubility of Ketones and AldehydesGood solvent for alcohols.Lone pair of electrons on oxygen of carbonyl can accept a hydrogen bond from O—H or N—H.Acetone and acetaldehyde are miscible in water.Chapter 18*FormaldehydeGas at room temperature.Formalin is a 40% aqueous solution.trioxane, m.p. 62Cformaldehyde,b.p. -21CformalinOCOCOCHHHHHHheatHCOHH2OHCHOHHOChapter 18*Infrared (IR) SpectroscopyVery strong C═O stretch around 1710 cm-1.Additional C—H stretches for aldehyde: Two absorptions at 2710 cm-1 and 2810 cm-1.Chapter 18*IR SpectraConjugation lowers the carbonyl stretching frequencies to about 1685 cm-1.Rings that have ring strain have higher C═O frequencies.Chapter 18*Proton NMR SpectraAldehyde protons normally absorb between d9 and d10. Protons of the α-carbon usually absorb between d2.1 and d2.4 if there are no other electron-withdrawing groups nearby.Chapter 18*1H NMR SpectroscopyProtons closer to the carbonyl group are more deshielded.Chapter 18*Carbon NMR Spectra of KetonesThe spin-decoupled carbon NMR spectrum of 2-heptanone shows the carbonyl carbon at 208 ppm and the α carbon at 30 ppm (methyl) and 44 ppm (methylene).Chapter 18*Mass Spectrometry (MS)Chapter 18*MS for ButyraldehydeChapter 18*McLafferty RearrangementThe net result of this rearrangement is the breaking of the α, β bond, and the transfer of a proton from the  carbon to the oxygen. An alkene is formed as a product of this rearrangement through the tautomerization of the enol.Chapter 18*Ultraviolet Spectra of Conjugated Carbonyl CompoundsConjugated carbonyl compounds have characteristic  -* absorption in the UV spectrum. An additional conjugated C═C increases max about 30 nm; an additional alkyl group increases it about 10 nm.Chapter 18*Electronic Transitions of the C═OSmall molar absorptivity.“Forbidden” transition occurs less frequently.Chapter 18*Industrial ImportanceAcetone and methyl ethyl ketone are important solvents.Formaldehyde is used in polymers like Bakelite.Flavorings and additives like vanilla, cinnamon, and artificial butter.Chapter 18*Chapter 18*Oxidation of Secondary Alcohols to KetonesSecondary alcohols are readily oxidized to ketones with sodium dichromate (Na2Cr2O7) in sulfuric acid or by potassium permanganate (KMnO4).Chapter 18*Oxidation of Primary Alcohols to AldehydesPyridinium chlorochromate (PCC) is selectively used to oxidize primary alcohols to aldehydes.Chapter 18*Ozonolysis of AlkenesThe double bond is oxidatively cleaved by ozone followed by reduction.Ketones and aldehydes can be isolated as products.Chapter 18*Friedel–Crafts ReactionReaction between an acyl halide and an aromatic ring will produce a ketone.Chapter 18*Hydration of AlkynesThe initial product of Markovnikov hydration is an enol, which quickly tautomerizes to its keto form. Internal alkynes can be hydrated, but mixtures of ketones often result.Chapter 18*Hydroboration–Oxidation of AlkynesHydroboration–oxidation of an alkyne gives anti-Markovnikov addition of water across the triple bond.Chapter 18*Show how you would synthesize each compound from starting materials containing no more than six carbon atoms.(a)(b)(a) This compound is a ketone with 12 carbon atoms. The carbon skeleton might be assembled from two six-carbon fragments using a Grignard reaction, which gives an alcohol that is easily oxidized to the target compound.Solved Problem 1SolutionChapter 18* An alternative route to the target compound involves Friedel–Crafts acylation.(b) This compound is an aldehyde with eight carbon atoms. An aldehyde might come from oxidation of an alcohol (possibly a Grignard product) or hydroboration of an alkyne. If we use a Grignard, the restriction to six-carbon starting materials means we need to add two carbons to a methylcyclopentyl fragment, ending in a primary alcohol. Grignard addition to an epoxide does this.Solved Problem 1 (Continued)Solution (Continued)Chapter 18* Alternatively, we could construct the carbon skeleton using acetylene as the two-carbon fragment. The resulting terminal alkyne undergoes hydroboration to the correct aldehyde.Solved Problem 1 (Continued)Solution (Continued)Chapter 18*Synthesis of Ketones and Aldehydes Using 1,3-Dithianes1,3-Dithiane can be deprotonated by strong bases such as n-butyllithium. The resulting carbanion is stabilized by the electron-withdrawing effects of two polarizable sulfur atoms. Chapter 18*Alkylation of 1,3-Dithiane Alkylation of the dithiane anion by a primary alkyl halide or a tosylate gives a thioacetal that can be hydrolyzed into the aldehyde by using an acidic solution of mercuric chloride.Chapter 18*Ketones from 1,3-DithianeThe thioacetal can be isolated and deprotonated.Alkylation and hydrolysis will produce a ketone.Chapter 18*Synthesis of Ketones from Carboxylic AcidsOrganolithiums will attack the lithium salts of carboxylate anions to give dianions. Protonation of the dianion forms the hydrate of a ketone, which quickly loses water to give the ketone.Chapter 18*Ketones from NitrilesA Grignard or organolithium reagent can attack the carbon of the nitrile.The imine is then hydrolyzed to form a ketone.Chapter 18*Aldehydes from Acid ChloridesLithium aluminum tri(t-butoxy)hydride is a milder reducing agent that reacts faster with acid chlorides than with aldehydes.Chapter 18*Lithium Dialkyl Cuprate ReagentsA lithium dialkylcuprate (Gilman reagent) will transfer one of its alkyl groups to the acid chloride.Chapter 18*Nucleophilic AdditionA strong nucleophile attacks the carbonyl carbon, forming an alkoxide ion that is then protonated.Aldehydes are more reactive than ketones. Chapter 18*The Wittig ReactionThe Wittig reaction converts the carbonyl group into a new C═C double bond where no bond existed before.A phosphorus ylide is used as the nucleophile in the reaction. Chapter 18*Preparation of Phosphorus YlidesPrepared from triphenylphosphine and an unhindered alkyl halide.Butyllithium then abstracts a hydrogen from the carbon attached to phosphorus.Chapter 18*Mechanism of the Wittig ReactionBetaine formationOxaphosphetane formationChapter 18*Mechanism for WittigThe oxaphosphetane will collapse, forming carbonyl (ketone or aldehyde) and a molecule of triphenyl phosphine oxide.Chapter 18*Show how you would use a Wittig reaction to synthesize 1-phenyl-1,3-butadiene.Solved Problem 2Chapter 18*This molecule has two double bonds that might be formed by Wittig reactions. The central double bond could be formed in either of two ways. Both of these syntheses will probably work, and both will produce a mixture of cis and trans isomers.You should complete this solution by drawing out the syntheses indicated by this analysis (Problem 18-16).Solved Problem 2 (Continued)Solution (Continued)Chapter 18*Hydration of Ketones and AldehydesIn an aqueous solution, a ketone or an aldehyde is in equilibrium with its hydrate, a geminal diol. With ketones, the equilibrium favors the unhydrated keto form (carbonyl).Chapter 18*Mechanism of Hydration of Ketones and AldehydesHydration occurs through the nucleophilic addition mechanism, with water (in acid) or hydroxide (in base) serving as the nucleophile.Chapter 18*Cyanohydrin FormationThe mechanism is a base-catalyzed nucleophilic addition: Attack by cyanide ion on the carbonyl group, followed by protonation of the intermediate.HCN is highly toxic.Chapter 18*Formation of IminesAmmonia or a primary amine reacts with a ketone or an aldehyde to form an imine. Imines are nitrogen analogues of ketones and aldehydes with a C═N bond in place of the carbonyl group.Optimum pH is around 4.5Chapter 18*Mechanism of Imine FormationAcid-catalyzed addition of the amine to the carbonyl compound group.Acid-catalyzed dehydration.Chapter 18*Other Condensations with AminesChapter 18*Formation of AcetalsChapter 18*Mechanism for Hemiacetal FormationMust be acid-catalyzed.Adding H+ to carbonyl makes it more reactive with weak nucleophile, ROH.Chapter 18*Acetal FormationChapter 18*Cyclic AcetalsAddition of a diol produces a cyclic acetal.The reaction is reversible.This reaction is used in synthesis to protect carbonyls from reactionChapter 18*Acetals as Protecting GroupsHydrolyze easily in acid; stable in base.Aldehydes are more reactive than ketones.Chapter 18*Reaction and DeprotectionThe acetal will not react with NaBH4, so only the ketone will get reduced.Hydrolysis conditions will protonate the alcohol and remove the acetal to restore the aldehyde.Chapter 18*Oxidation of AldehydesAldehydes are easily oxidized to carboxylic acids.Chapter 18*Reduction ReagentsSodium borohydride, NaBH4, can reduce ketones to secondary alcohols and aldehydes to primary alcohols. Lithium aluminum hydride, LiAlH4, is a powerful reducing agent, so it can also reduce carboxylic acids and their derivatives.Hydrogenation with a catalyst can reduce the carbonyl, but it will also reduce any double or triple bonds present in the molecule. Chapter 18*Sodium BorohydrideNaBH4 can reduce ketones and aldehydes, but not esters, carboxylic acids, acyl chlorides, or amides.Chapter 18*Lithium Aluminum HydrideLiAlH4 can reduce any carbonyl because it is a very strong reducing agent.Difficult to handle.Chapter 18*Catalytic HydrogenationWidely used in industry.Raney nickel is finely divided Ni powder saturated with hydrogen gas.It will attack the alkene first, then the carbonyl.Chapter 18*Deoxygenation of Ketones and AldehydesThe Clemmensen reduction or the Wolff–Kishner reduction can be used to deoxygenate ketones and aldehydes.Chapter 18*Clemmensen ReductionChapter 18*Wolff–Kishner ReductionForms hydrazone, then heat with strong base like KOH or potassium tert-butoxide.Use a high-boiling solvent: ethylene glycol, diethylene glycol, or DMSO.A molecule of nitrogen is lost in the last steps of the reaction.

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